[Python] ์ ‘๋ฏธ์‚ฌ์ธ์ง€ ํ™•์ธํ•˜๊ธฐ

2024. 5. 30. 18:08ใ†[๐Ÿ’ปPython] pearl's python ๋ณ‘์•„๋ฆฌ ํƒˆ์ถœ๊ธฐ ๐Ÿฃ

<๋ฌธ์ œ ์„ค๋ช…>
์–ด๋–ค ๋ฌธ์ž์—ด์— ๋Œ€ํ•ด์„œ ์ ‘๋ฏธ์‚ฌ๋Š” ํŠน์ • ์ธ๋ฑ์Šค๋ถ€ํ„ฐ ์‹œ์ž‘ํ•˜๋Š” ๋ฌธ์ž์—ด์„ ์˜๋ฏธํ•ฉ๋‹ˆ๋‹ค. ์˜ˆ๋ฅผ ๋“ค์–ด, "banana"์˜ ๋ชจ๋“  ์ ‘๋ฏธ์‚ฌ๋Š” "banana", "anana", "nana", "ana", "na", "a"์ž…๋‹ˆ๋‹ค.๋ฌธ์ž์—ด my_string๊ณผ is_suffix๊ฐ€ ์ฃผ์–ด์งˆ ๋•Œ, is_suffix๊ฐ€ my_string์˜ ์ ‘๋ฏธ์‚ฌ๋ผ๋ฉด 1์„, ์•„๋‹ˆ๋ฉด 0์„ return ํ•˜๋Š” solution ํ•จ์ˆ˜๋ฅผ ์ž‘์„ฑํ•ด ์ฃผ์„ธ์š”.
def solution(my_string, is_suffix):
    num = len(is_suffix)
    num1 = len(my_string)

    if my_string[num1 - num:] == is_suffix:
        return 1
    else:
        return 0